(-3)=7x^2-4

Solution for (-3)=7x^2-4 equation:

(-3)=7x^2-4

We move all terms to the left:

(-3)-(7x^2-4)=0

We add all the numbers together, and all the variables

-(7x^2-4)-3=0

We get rid of parentheses

-7x^2+4-3=0

We add all the numbers together, and all the variables

-7x^2+1=0

a = -7; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-7)·1
Δ = 28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{28}=\sqrt{4*7}=\sqrt{4}*\sqrt{7}=2\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{7}}{2*-7}=\frac{0-2\sqrt{7}}{-14}
=-\frac{2\sqrt{7}}{-14}
=-\frac{\sqrt{7}}{-7}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{7}}{2*-7}=\frac{0+2\sqrt{7}}{-14}
=\frac{2\sqrt{7}}{-14}
=\frac{\sqrt{7}}{-7}
$